What Determines the Galois Group of a Polynomial's Splitting Field?

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Discussion Overview

The discussion revolves around determining the Galois group of the splitting field of the polynomial $f(x)=x^3+x^2-2x-1$ over the rational numbers. Participants explore methods related to automorphisms, discriminants, and the properties of the roots of the polynomial.

Discussion Character

  • Technical explanation, Mathematical reasoning, Debate/contested

Main Points Raised

  • One participant suggests that the automorphisms of the polynomial are defined by the images of its roots and that these automorphisms act as permutations of the roots, indicating a need to check which automorphisms belong to the Galois group.
  • Another participant proposes computing the discriminant of the cubic polynomial and checking whether it is a square in the relevant field, stating that if the discriminant is a square, the Galois group is $A_3$, while if it is not a square, the group is $S_3$.
  • A later reply requests further clarification on the initial explanation regarding automorphisms and their relation to the Galois group.

Areas of Agreement / Disagreement

Participants express different approaches to determining the Galois group, with no consensus reached on the method or the implications of the discriminant's properties.

Contextual Notes

The discussion does not resolve the assumptions regarding the irreducibility of the polynomial or the specific properties of the discriminant in relation to the Galois group.

mathmari
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Hey! :o

We consider the polynomial $f(x)=x^3+x^2-2x-1 \in \mathbb{Q}[x]$ and let $E$ be its splitting field.

How can we find the group $Gal(E/\mathbb{Q})$ ?? (Wondering)
 
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Hi,

The automorphisms will be well defined with the image of the roots of $f$, and are also permutations over the roots, so you only have to check when a so defined automorphism is in the Galois group.
 
Fallen Angel said:
Hi,

The automorphisms will be well defined with the image of the roots of $f$, and are also permutations over the roots, so you only have to check when a so defined automorphism is in the Galois group.

Could you explain it further to me?? (Wondering)
 
Compute the discriminant of the cubic polynomial (it is irreducible). Then check if the discriminant is a square or not, in the square field. If it is a square the group is $A_3$, if it is a non-square then it is $S_3$.
 

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