- #1
TheronSimon
- 37
- 0
Homework Statement
(V2-V1)^2 = 552+452-2*55*45*cos135
= 92.5m/s
My question is how to get from the first equation to the answer...
What Does 92.5 m/s Represent in the Equation (V2-V1)^2?
- Thread starter TheronSimon
- Start date
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Homework Help Overview
The discussion revolves around the equation (V2-V1)^2 = 552 + 452 - 2*55*45*cos135, specifically questioning the representation of 92.5 m/s within this context. Participants are examining the application of the cosine law and its implications in the problem.
Discussion Character
- Exploratory, Assumption checking, Conceptual clarification
Approaches and Questions Raised
- Some participants question the correctness of the calculation leading to 92.5 m/s, suggesting it may not have been solved accurately. Others propose that the equation resembles an application of the cosine law, indicating a potential typographical error in the course material. There is also inquiry about what 92.5 m/s specifically represents in the context of V2, V1, or their difference.
Discussion Status
The discussion is ongoing, with participants exploring different interpretations of the equation and its components. Some have offered insights into possible errors and have encouraged the original poster to provide more context for clarity.
Contextual Notes
There is mention of potential typos in course material and the need for additional background context to fully understand the problem. Participants are also reflecting on their own experiences and distractions that may have contributed to oversight in calculations.
(V2-V1)^2 = 552+452-2*55*45*cos135
= 92.5m/s
My question is how to get from the first equation to the answer...
- #2
emailanmol
- 296
- 0
552+452-2*55*45*cos135
Is not solved correctly.
It doesn't come up to 92.5(assuming the calculation you were working on didn't need change of units.
Is not solved correctly.
It doesn't come up to 92.5(assuming the calculation you were working on didn't need change of units.
- #3
TheronSimon
- 37
- 0
its something from the course material, so i guess its just wrong...
- #4
emailanmol
- 296
- 0
Yeah, it sounds like wrong.
If you can perhaps add some back ground context we may be able to work out what the text wanted to convey :-)
If you can perhaps add some back ground context we may be able to work out what the text wanted to convey :-)
- #5
gneill
Mentor
- 20,989
- 2,934
TheronSimon said:
Looks suspiciously like an application of the cosine law where the exponents have lost their superscipt. Thus:
##x^2 = 55^2 + 45^2 - 2\cdot55\cdot45\cdot cos(135°) ##
solve for x.
- #6
TheronSimon
- 37
- 0
haha! there we go thanks! i guess it it was just a typo in the course material.
- #7
emailanmol
- 296
- 0
OMG!
How did i miss that!
That was incredible observation gneill
How did i miss that!
That was incredible observation gneill
- #8
gneill
Mentor
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emailanmol said:
I attribute it to to many hours doing math and not enough enjoying St. Patrick's day parties. I shall have to make amends
- #9
jey1234
- 38
- 0
emailanmol said:
I agree. Remarkable
- #10
PeterO
Homework Helper
- 2,442
- 67
TheronSimon said:
What is supposed to be 92.5 m/s
V2, V1 or the difference V2 - V1 ?
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