What Does Constant Acceleration Mean in Mechanics?

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Constant acceleration in mechanics refers to a situation where the acceleration remains the same over time, which does not imply that speed is constant. If speed is constant, acceleration is zero, meaning there is no change in velocity. However, with constant acceleration, the speed can change, as described by the equation v = v0 + at, where v0 is the initial velocity, a is the acceleration, and t is time. An example is a falling apple, which experiences constant acceleration due to gravity but does not fall at a constant speed. Understanding these distinctions is crucial for solving mechanics problems effectively.
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Just wanted to clarify here:

Sometime in mechanics exercises it is mentioned that the speed should be considered as constant, which in return means that the acceleration a = 0 ms-2.

Now if it is mentioned that the acceleration should be considered as constant what does that mean? That the speed remains constant too?

Please explain simply thanks :-)
 
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Natasha1 said:
Just wanted to clarify here:

Sometime in mechanics exercises it is mentioned that the speed should be considered as constant, which in return means that the acceleration a = 0 ms-2.

Now if it is mentioned that the acceleration should be considered as constant what does that mean? That the speed remains constant too?

Please explain simply thanks :-)
A falling apple undergoes a constant acceleration (i.e g), does that means the apple is falling at a constant speed?
I think you should go over your textbook again, for a constant acceleration, we have:
v = v0 + at, where:
v0 is the initial velocity, a is the acceleration, and t is the time spent.
:)
 
Oops!
If the SPEED is constant, it means that the acceleration is orthogonal to the velocity at all times; you can perfectly well have non-zero acceleration in this case.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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