What Does Fd Represent in Net Force Calculations?

Click For Summary
In net force calculations, Fd is not a standard term and its meaning can vary based on context. The discussion suggests that Fd could represent a downward force, but clarification is needed since the terms Fa (applied force) and Ff (frictional force) are more commonly understood. Participants emphasize the importance of providing the complete problem for accurate assistance. Without additional details, it is challenging to determine the exact nature of Fd. Overall, more context is essential for a precise interpretation of the forces involved.
reganw
Messages
19
Reaction score
0
I'm trying to calculate the acceleration of an object but first I need to calculate the net force. For this question we were told Fnet = Fa-Fd-Ff.. just wondering what Fd is?

Thank you in advance.
 
Last edited:
Physics news on Phys.org
not ! calculate net force (N) how can including the work done (J).:smile:

You should check out your question purposely that what kind of the force(Fd) is.
 
xiaoB said:
not ! calculate net force (N) how can including the work done (J).:smile:

You should check out your question purposely that what kind of the force(Fd) is.

hmm.. I just don't know what it could be.. there's Fn, Fa, Ff, Fg all in the question but I don't know where the Fd comes from.. maybe Fdown?
 
Why don't you post the actual question, in it's entirety?
 
Redbelly98 said:
Why don't you post the actual question, in it's entirety?

It's a simulation, everything can be altered so there isn't really a question to post. And I can't post the link to it because it's an internal website.
 
We have no information other than there is an object with 3 forces acting on it, and these forces are to be labeled Fa, Fd, and Ff. Is there really nothing else you can tell us about the problem?

Ff usually means a frictional force. But Fa and Fd do not have a usual definition that I am aware of, though Fa might be used for an applied force. But here I am only guessing at the things you already know, but have neglected to tell us. I'm afraid that without more information, it is unlikely that we can help out.
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
Replies
9
Views
2K
Replies
30
Views
4K
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
919
  • · Replies 1 ·
Replies
1
Views
1K