What does it mean to satisfy the Schrodinger equation?

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Homework Help Overview

The discussion revolves around understanding what it means for a wave function to "satisfy" the Schrödinger equation, specifically in the context of the 2p wave functions of the hydrogen atom and their relationship to the radial Schrödinger equation.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the meaning of satisfying the Schrödinger equation, with one asking for clarification on the process of differentiation involved in the equation. Others discuss the implications of their calculations and the constants that should emerge from their work.

Discussion Status

The discussion is ongoing, with participants sharing their attempts at solving the problem and seeking clarification on specific steps. Some guidance has been offered regarding checking work and expressing constants in terms of the Bohr radius, but no consensus has been reached on the solution.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the amount of direct assistance they can receive. There is an emphasis on ensuring that all derivatives and calculations are correctly performed to satisfy the equation.

warfreak131
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What does it mean to "satisfy" the Schrödinger equation?

Homework Statement



Show that the 2p wave functions of the hydrogen atom satisfy the radial Schrödinger eq.

One of the radial equations for the 2p state is [tex]\frac{1}{\sqrt{96 \pi a^{3}}} \frac{r}{a} e^{\frac{-r}{2a}}[/tex]

Homework Equations


The Attempt at a Solution



[tex][\frac{-\hbar^2}{2m}\frac{1}{r^2}\frac{d}{dr}(r^2\frac{d}{dr})+\frac{l(l+1)\hbar^2}{2mr^2}+V(r)]R=ER[/tex]

I took the derivative with respect to r, and followed all the subsequent derivatives, and the answer is really messy. What exactly am I looking for when something "satisfies" the equation?
 
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You're looking to see if the operator on the left, when acting upon the wave function (or in this case part of it), returns a constant times that same wave function.

So if I had something like [tex]f(x)=e^{-3x/5}[/tex] and were asked if f(x) satisfies

[tex]{{df}\over{dx}} = Af(x)[/tex].

What you get when you do the derivative of f(x) is the -3/5 times the function again. Thus, f(x) satisfies the equation with A = -3/5. Same idea here
 


Ok, I see. So what should I do since all the derivates and sums don't come out to a nice constant?
 


Check your work :P Or show us your work
 


okay, but quick question first
[tex]\frac{d}{dr}(r^2\frac{d}{ dr})[/tex]

is this line asking you to take the derivative of R, multiply it by r^2, and then take the derivative of the resulting equation?
 


warfreak131 said:
okay, but quick question first
[tex]\frac{d}{dr}(r^2\frac{d}{ dr})[/tex]

is this line asking you to take the derivative of R, multiply it by r^2, and then take the derivative of the resulting equation?

Yup!
 


okay, i used mathematica, i created functions for each term, did all the necessary derivatives and additions, and what i got was

(2 a^2 e^2 m - 8 a h^2 pi epsilon + h^2 pi r epsilon)/(8 a^2 m pi r epsilon)

this answer was close with the exception of r, everything else is a constant
 

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Express the Bohr radius in terms of the other constants. You should find the first two terms in the numerator will cancel.
 


vela said:
Express the Bohr radius in terms of the other constants. You should find the first two terms in the numerator will cancel.

ill try that, thanks
 

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