C/C++ What does the modulus operator mean in a C++ if statement?

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The discussion centers on understanding an if statement that utilizes the modulus operator. The expression checks if a specific element in the 'randoms' array, determined by the calculation (x * 3) + y, is odd. The modulus operator (%) returns the remainder of a division, so when used with 2, it indicates whether the number is odd (true) or even (false). If the element is odd, the code within the if statement will execute.
FallArk
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I have run into an if statement as shown below:

if (randoms[(x * 3) + y] % 2)

I don't really understand what this means.
Thank you for helping!
 
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The [m]%[/m] symbol is the modulus operator, and so the expression [m]n % 2[/m] will be true if n is odd (there is a remainder when dividing by 2) and false if n is even (there is no remainder when dividing by 2).

So, the statement:

[m]if (randoms[(x * 3) + y] % 2)[/m]

Is looking to see if the [m]((x*3) + y)[/m]th element of the [m]randoms[/m] array is odd, and if so, execute some code.
 
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