What does the operator C^3 represent in Bra-ket notation?

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Discussion Overview

The discussion revolves around the interpretation of the operator C^3 in Bra-ket notation, particularly in relation to its action on the states |1> and |2>. Participants explore the implications of applying the operator multiple times and whether it behaves like an identity function.

Discussion Character

  • Exploratory
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • Some participants propose that if C is an operator such that C|1> = |1> and C|2> = |2>, then C^3 |1> could be interpreted as |1>|1>|1> or |1>^3.
  • Others question whether C^3 |1> actually equals |1>|1>|1> and suggest that it might just equal |1>.
  • One participant suggests that if C^3 |2> is calculated, it would yield |2>, indicating that C is not the identity function.
  • Another participant acknowledges a misunderstanding regarding the action of C on |2> and suggests that it might be the identity function, but expresses uncertainty based on limited examples.
  • Concerns are raised about the notation |1>|1>|1> being nonsensical in this context, and the idea that there is no concept of a power of a vector is mentioned.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the nature of the operator C or the interpretation of C^3. Multiple competing views remain regarding whether C acts as an identity function and the validity of the notation used.

Contextual Notes

There are limitations in the discussion, including assumptions about the operator C and its properties, as well as the implications of the notation used for multiple applications of the operator.

rsaad
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Hi
If C is an operator such that C|1> = |1> and C|2>=|2>, then C^3 |1>= |1>|1>|1> =|1> ^ 3 ? If yes, then what does this C^3 represent?
:confused:
 
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rsaad said:
Hi
If C is an operator such that C|1> = |1> and C|2>=|2>, then C^3 |1>= |1>|1>|1> =|1> ^ 3 ? If yes, then what does this C^3 represent?

Welcome to PF, rsaad!

If f is a function such that f(x)=x.
And f3(x) denotes f(f(f(x))).
What is f3(x)?
 
OMG! That makes sense! Thank you soooo much!
 
f^3 x is a function again =)
 
You're welcome. :wink:

rsaad said:
f^3 x is a function again =)

Yeah... which function?

And is C^3 |1> = |1>|1>|1>?
 
No. it is just |1>
 
So that's an identity function
 
Right!
 
Your C is not the identity function!
Try to calculate C^3 |2> to see the difference.

Edit: Ignore that post, see below.
 
Last edited:
  • #10
mfb said:
Your C is not the identify function!
Try to calculate C^3 |2> to see the difference.

C^3 |2> = C C C |2> = C C |2> = C |2> = |2>

Where is the difference?
 
  • #11
Oh sorry, I somehow read C |2> = 2 |2> in the first post. You are right.
Ok, it might be the identity function (but we cannot be sure based on 2 examples only).
 
  • #12
The notation |1>|1>|1> doesn't make sense here.
 
  • #13
There's no such thing as the 3rd or any power of a vector.
 

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