pellman said:
It is an X like in a cross product but with a vertical line connecting upper-left and lower-left endpoints. I will write it as |X . Example context:
R^4 |X SL(2,C)
where the R and C are real numbers and complex numbers.
fresh_42 said:
But I don't know how the operation goes. Often it is a conjugation, but ##\mathbb{R}^4## is additive and ##SL(2,\mathbb{C})## multiplicative. So maybe in this case the Euclidean space is the normal subgroup, because not all authors follow the rule:
$$
K \leq G = H \ltimes K \trianglerighteq H
$$
Some use it the other way around. In any case is it important how the group multiplication is defined to see which one is the normal one.
Well, the inhomogenous ##\text{SL}(2,\mathbb{C})## is the semidirect product of ##(\mathbb{R}^4, +)## and ##(\text{SL}(2,\mathbb{C}),\cdot)##, where + stands for the addition of 4-tuples of real numbers and the dot stands for matrix multiplication. The group ##(\mathbb{R}^4, +)## is an abelian normal subgroup of the semidirect product group.
More precisely:
$$\text{ISL}(2,\mathbb{C}) := \mathbb{R}^4 \ltimes \text{SL}(2,\mathbb{C}) =\left\{ (x,A), x\in\mathbb{R}^4, A \in\text{SL}(2,\mathbb{C}) | (x.A) \ltimes (y,B) = (x+A \star b, A \cdot B), \forall x,y\in\mathbb{R}^4, \forall A,B\in\text{SL}(2,\mathbb{C})\right\} $$
$$ (\mathbb{R}^4, +) \trianglerighteq \text{ISL}(2,\mathbb{C}) $$
The ## A \star b ## is the action of ## \text{SL}(2,\mathbb{C}) ## on the 4D-Minkowski spacetime defined by a matrix representation of the restricted Lorentz group (## A\in \text{SL}(2,\mathbb{C}) \mapsto \bf{\Lambda}_{A} \in \mathcal{L}_{+}^{\uparrow} ##).