What does this - ^ mean when it is over a value?

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The discussion clarifies that the symbol "^" over a variable, such as "r," indicates a unit vector, which is essential in vector fields like the electric field. In the equation for the electric field, this notation signifies that the variable represents a normalized direction rather than a scalar quantity. The electric field is a vector field, meaning it has both magnitude and direction, while the other terms in the equation are scalars. The unit vector points away from the central charge, providing necessary directional information. Understanding this notation is crucial for accurately interpreting vector equations in physics.
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What does this -- "^" mean when it is over a value?

The equation for an electric field is E = 1/4pie(epsilon) * Q/r^2 *(^r" I do not know how to put the roof over the r so i put it right next to it")

What does this value mean because I have also seen it occur with distance. It seems to me like it does nothing for the final answer. What does it do?
 
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The hat is a kind of decoration to put on symbols -- it's just another way to vary a symbol, like varying the font or the case or the language.

One common use for the hat is to indicate the variable represents a unit vector, specifically the normalization of the ordinary vector represented by the same base letter.
 


\mathbf E = \frac 1 {4\pi\epsilon_0}\,\frac Q{r^2}\hat{\mathbf r}

The electric field is a vector field rather than a scalar field. All of the terms on the right hand side except the final \hat{\mathbf r} are scalars. That final \hat{\mathbf r} is a unit vector that points away from the central charge.
 
I do not have a good working knowledge of physics yet. I tried to piece this together but after researching this, I couldn’t figure out the correct laws of physics to combine to develop a formula to answer this question. Ex. 1 - A moving object impacts a static object at a constant velocity. Ex. 2 - A moving object impacts a static object at the same velocity but is accelerating at the moment of impact. Assuming the mass of the objects is the same and the velocity at the moment of impact...

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