What Electric Field is Needed to Ionize Neon at Atmospheric Pressure?

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SUMMARY

The electric field required to ionize neon gas at atmospheric pressure is determined by its ionization energy of 22 eV and the mean free path of electrons, which is approximately 20 x 10^-6 m. To achieve ionization, the electric field must be strong enough to accelerate electrons to the necessary energy level before they collide with neon atoms. This discussion emphasizes the importance of understanding collision probabilities and energy gain in the context of gas ionization.

PREREQUISITES
  • Understanding of ionization energy and its significance in gas physics
  • Familiarity with the concept of mean free path in gas dynamics
  • Basic knowledge of electric fields and their effects on charged particles
  • Experience with calculations involving energy and distance in physics
NEXT STEPS
  • Research the relationship between electric fields and ionization processes in gases
  • Explore the concept of mean free path and its calculation in different gases
  • Learn about the role of collision cross-sections in gas ionization
  • Investigate experimental methods for measuring ionization thresholds in gases
USEFUL FOR

Physicists, electrical engineers, and students studying plasma physics or gas ionization processes will benefit from this discussion.

alex_thaiboy
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What is a first order approzimation for the electric field to ionize neon? (ioniztion energy 22eV) at atmospheric pressure?
Hint: The probability of collision of the electron with the gas molecule is called electron mean free path. The mean free path of the electron at atmospheric pressure in Ne gas is about 20*10^-6 m. This means the electron will gain energy over 20*10^-6m.
 
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