What exactly is a 2nd order differential equation?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
5 replies · 3K views
Venomily
Messages
14
Reaction score
0
A first order DE models the rate of change, e.g. when decay is proportional to time we have the DE: dM/dt = -K.M; this is describing that rate of change mathematically. Am I correct in saying that a 2nd order DE describes the rate of rate of change?

Also, can anyone explain any application of 2nd order DEs to me? I understand it mathematically, but I am interested in how it works in practice like that decay example I pointed out above, hence this post.
 
Physics news on Phys.org
D H said:
Classical physics is chock full of second order ODEs. F=ma, for example.

Not to mention electrical circuits with an inductor, resistor, and capacitor.
 
D H said:
Classical physics is chock full of second order ODEs. F=ma, for example.

Mark44 said:
Not to mention electrical circuits with an inductor, resistor, and capacitor.

Thanks, but can you go through an example with me? actually point out a real life application (which you guys did) but also deriving a 2nd order DE to model it step by step.
 
If you throw a ball directly upward with initial speed 10 m/s, the basic physics law is "force= mass times acceleration". In this case, the only force (neglecting air resistance) is gravity: -mg. Since acceleration is the second derivative of the position function, taking x to be the height above the ground at time t, we have the differential equation
[tex]m\frac{d^2x}{dt^2}= -mg[/tex]
with initial conditions x(0)= 0, x'(0)= 10.