The discussion focuses on calculating the focal length required for a diverging lens to achieve a magnification of 0.60x for an object positioned 1.40 meters away. The relevant equations include the magnification formula M=hi/ho and the lens formula 1/do + 1/di = 1/f. The solution involves determining the image distance (di) as -0.84 meters, leading to the calculation of the focal length (f) using the lens formula. The final focal length is approximately -1.42 meters, indicating the lens is diverging.
PREREQUISITESStudents in optics, physics educators, and anyone interested in understanding lens behavior and magnification principles.
Is that + sign correct?Taylor Marks said:Homework Statement
What focus is needed for in order for a diverging lens to produce a magnification of 0.60x on an object located 1.40 meters away?
Homework Equations
M=hi/ho
1/do + 1/di = 1/f
M= -di/do
The Attempt at a Solution
-di / 1.4 = 0.6
1/1.4 + 1/.84 =1/f
-di=0.84
1.42