What happens when a strong base is added to a weak acid?

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SUMMARY

When a strong base, such as sodium hydroxide (NaOH), is added to a weak acid like acetic acid, the strong base neutralizes the weak acid, leading to the formation of water and acetate ions. The reaction favors the reverse process, where the hydronium ion (H3O+) reacts with hydroxide ions (OH-) to produce water, effectively stabilizing the pH. The Henderson-Hasselbalch equation is recommended for calculating pH after complete neutralization, as the resulting solution primarily consists of sodium acetate, which undergoes hydrolysis.

PREREQUISITES
  • Understanding of weak acids and their dissociation, specifically acetic acid.
  • Knowledge of strong bases and their dissociation, particularly sodium hydroxide.
  • Familiarity with the concept of equilibrium in chemical reactions.
  • Proficiency in using the Henderson-Hasselbalch equation for pH calculations.
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  • Study the Henderson-Hasselbalch equation in detail for pH calculations.
  • Research the hydrolysis of acetate ions in aqueous solutions.
  • Explore the concepts of acid-base equilibrium and its applications in titration.
  • Examine the properties and behavior of weak acids and strong bases in various chemical reactions.
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Chemistry students, educators, and anyone interested in understanding acid-base reactions, particularly in the context of weak acids and strong bases.

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Homework Statement


In my textbook, they don't necessarily explain what happens when we add a base to a weak acid (e.g. acetic acid)...so I was wondering if anyone can tell me if I got it down:

-Like if we have acetic acid (which is a weak base) in water, it will form an equilibrium and form the hydronium ion (is this a strong conjugate acid?) and the acetate ion (strong conjugate base) as products.

-If we add NaOH, this will dissociate into Na+ and OH-...the OH- being a strong base will likely react with the strong conjugate acid (hydronium ion) in order to negate the effects of the added base.

-So essentially, this will favour the reverse reaction (does it bring it to completion since its a strong conjugate acid?)

-In the end, the OH- that reacts with the hydronium ion will form water which doesn't affect the pH...?

I don't really feel confident about my understanding though...it seems that I'm overthinking it...

Homework Equations





The Attempt at a Solution

 
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lha08 said:
Like if we have acetic acid (which is a weak base)

Let's call it a weak acid.

When you add strong base it will neutralize the acid, you may assume neutralization was quantitative. There is always some hydrolysis of the conjugate base, at the same time acid left dissociates lowering pH. Safest way of calculating pH is to assume neutralization went to completion and use Henderson-Hasselbalch equation.

When all acid has been neutralized (which means there is just a solution of sodium acetate) situation is dominated by hydrolysis, and you can calculate pH assuming you have a solution of a weak base (acetate).
 
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