What Happens When Snell's Law Is Exceeded?

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SUMMARY

When the ratio v2/v1 exceeds 1 in Snell's Law, it is possible to make sinβ approach 1, leading to sinθ exceeding 1. However, this results in a scenario where the angle θ does not exist, indicating total internal reflection. The correct formulation of Snell's Law is sin(α)/sin(β) = v_a/v_b, where α and β represent the angles of incidence and refraction, respectively.

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MHD93
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Hi people..

Snell's law reads sinθ = (v2/v1)sinβ

Suppose that v2/v1 > 1, then we can make sinβ as close to 1 as we like, even close enough to make sinθ>1 as Snell's law states.

So what's wrong?
 
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Hi Mohammad_93! :smile:

(try using the X2 button just above the Reply box :wink:)
Mohammad_93 said:
Suppose that v2/v1 > 1, then we can make sinβ as close to 1 as we like, even close enough to make sinθ>1 as Snell's law states.

So what's wrong?

In that case, θ does not exist, and there is total internal reflection. :wink:
 
Try to be consistent with your notation.
Snells law is written as
Sinia/Sinib = va/vb
 

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