What happens when two of the evanescent particles that Hawking

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The discussion centers on the behavior of evanescent particles, as described by Stephen Hawking, when two such particles overlap in space and time. Due to quantum mechanical effects, the precise location of these particles is not well-defined, leading to a probability distribution for their separation. If two evanescent particles were to appear at the same location, they would not contribute to Hawking radiation and would likely annihilate each other shortly thereafter. This highlights the complex nature of virtual particles in quantum mechanics.

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thepemberton
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Hello,

I didn't know where else to ask this, but I'm quite curious. What happens when two of the evanescent particles that Hawking describes, pop into existence at the same place and the same instant effectively overlapping each other?

The source that sparked this question: http://www.economist.com/node/17144843?story_id=17144843&fsrc=rss#black_and_light"

Many thanks!
 
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Hi thepemberton, welcome to PF. Due to quantum mechanical (QM) effects the exact location and time of these particles appearing are pretty close to overlapping, there is some probability distribution that describes their likely initial separations. If they---hypothetically---appeared exactly in the same space (keep in mind that an exact place isn't always well defined in QM) then they simply wouldn't be able to participate in hawking radiation. They would most likely annihilate shortly after as most 'evanescent' (virtual) particles do. Does that help?
 


Thanks zhermes! That question was bugging me. I'll read up a little more on virtual particles!
 

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