MHB What happens when you expand and factor (a + b + c)^3 - a^3 - b^3 - c^3?

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To factor the expression (a + b + c)^3 - a^3 - b^3 - c^3, the initial step involves expanding (a + b + c)^3. This allows for the cancellation of the terms -a^3, -b^3, and -c^3. The problem can be approached by rewriting it as the difference of cubes for [(a + b + c)^3 - a^3] and the sum of cubes for [b^3 + c^3]. Applying these methods will lead to significant term cancellations. Ultimately, the goal is to simplify the expression effectively through these algebraic identities.
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Factor the expression.

(a + b + c)^3 - a^3 - b^3 - c^3

I believe the best way to tackle this problem is to expand (a + b + c)^3. By doing so, I should be able to cancel out -a^3 - b^3 - c^3, right?
 
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RTCNTC said:
Factor the expression.

(a + b + c)^3 - a^3 - b^3 - c^3

I believe the best way to start problem is by expanding
(a + b + c)^3. By doing so, I should be able to cancel out
-a^3 - b^3 - c^3, right?
Start by writing it as $[(a+b+c)^3 - a^3] - [b^3 + c^3]$, and factor the contents of each of the square brackets as the difference (or sum) of two cubes.
 
The difference of cubes is applied to
[(a + b + c)^3 - a^3] and the sum of cubes to [b^3 + c^3].

Correct?
 
RTCNTC said:
The difference of cubes is applied to
[(a + b + c)^3 - a^3] and the sum of cubes to [b^3 + c^3].

Correct?
Yes! What happens when you do that?
 
Opalg said:
Yes! What happens when you do that?

I have not completed the problem. So, my guess is that after applying the sum and difference of cubes, lots of terms will get canceled in the process.
 
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