The distinction between 'pure' and 'mixed' applies to ensembles of quantum systems, not the possible states of individual quantum systems.
Consider the following examples. You have N spin 1/2 systems:
1. All of your spin systems are identically prepared in a S_z= +1/2 eigenstate. This is a pure ensemble.
2. All of your spins are identically prepared in the same linear combination of + and - Sz eigenstates. This is also a pure ensemble.
3. 25% percent of your spin systems are prepared like in 1 above. 75% are prepared in the state described in 2. This is a mixed ensemble.
Mathematically the difference is easily seen in terms of the density matrix [itex]\hat{\rho}[/itex] of the ensemble if you are familiar with that idea. For a pure ensemble, the trace of the square of the density operator is a maximum at one: [itex]Tr(\hat{\rho}^2)=1[/itex]. For any mixed ensemble the trace of [itex]\hat{\rho}^2[/itex] is less than 1. Also, for a pure state, the density operator is indempotent, i.e. [itex]\hat{\rho}^2=\hat{\rho}[/itex] So, if you are able to write down the density matrix of the system, you have an easy way of determining whether a state is pure or mixed.