Darkrise666
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Here's the problem.
Theorem: If n^2+1 is odd, then n is even. Give indirect proof.
Theorem: If n^2+1 is odd, then n is even. Give indirect proof.
The theorem states that if n² + 1 is odd, then n must be even. An indirect proof involves assuming the opposite, that n is odd, which leads to a contradiction. If n is odd, then n² is also odd, making n² + 1 even, contradicting the original statement. Therefore, the assumption is false, confirming that n must be even when n² + 1 is odd.
PREREQUISITESMathematics students, educators, and anyone interested in formal proof techniques and number theory.