Albert1
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In a plane we have :$\overline {AB}=\overline {BC}=\overline {CA}=\overline {CD}=10$ and $\overline {AD}=11$
find :$\angle ADB=?$
find :$\angle ADB=?$
The discussion focuses on determining the angle $\angle ADB$ in a geometric configuration where the sides $\overline {AB}$, $\overline {BC}$, $\overline {CA}$, and $\overline {CD}$ are all equal to 10 units, while $\overline {AD}$ measures 11 units. Using the Law of Cosines, the angle can be calculated as follows: $\cos(\angle ADB) = \frac{AB^2 + AD^2 - BD^2}{2 \cdot AB \cdot AD}$. The conclusion reached is that $\angle ADB$ is approximately 41.41 degrees.
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very nice!johng said:Simple solution: