What is Brewster's Angle for Sunlight Reflecting on Water?

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SUMMARY

The discussion centers on calculating Brewster's angle for sunlight reflecting off water with a refractive index of 1.33. The calculated Brewster's angle (θo) is 53°, derived using the formula tan(θo) = n2/n1, where n2 is the refractive index of water and n1 is the refractive index of air. Participants are encouraged to apply Snell's Law to determine the angle of refraction and to utilize geometric principles to find the angle between the reflected and refracted beams.

PREREQUISITES
  • Understanding of Brewster's angle and its significance in optics
  • Familiarity with Snell's Law for calculating angles of refraction
  • Basic knowledge of trigonometric functions and their applications in physics
  • Ability to interpret and create geometric sketches for optical phenomena
NEXT STEPS
  • Research Snell's Law and its applications in different media
  • Explore the concept of polarization and its relevance in optics
  • Learn about the geometric relationships in optics, particularly involving reflection and refraction
  • Investigate the implications of Brewster's angle in photography and visual arts
USEFUL FOR

Students studying optics, physics enthusiasts, and professionals in fields related to photography and visual sciences who seek to understand the behavior of light at interfaces.

squirrelly
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Homework Statement



As the sun rises over a still pond, an angle will be reached where its image seen on the water's surface(n=1.33) will be completely polarized in a plan parallel to the surface.

i) Compute the appropriate incident angle(that is the polarization or Brewster's angle)

ii)At what angle(from the normal) will the transmitted beam propagate through the water(that is, what is the angle of refraction)

iii)What is the angle between the reflected and refracted beams.



The Attempt at a Solution


i) n2cos(θo)-n1√[(1-(n21/n22)sin2o)]

(n22/n21)=tan2o)+1-(n21/n22)tan2o)

tan2o)={[(n22/n21-1]/[1-(n21/n22)]}=(n22/n21)

tan(θo)=(n2/n1)=(1.33/1)

θo=tan-1(1.33)=53°

Homework Statement




and that's as far as I could get. :/ I am pretty sure part(i) is right.
 
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squirrelly said:

Homework Statement



As the sun rises over a still pond, an angle will be reached where its image seen on the water's surface(n=1.33) will be completely polarized in a plan parallel to the surface.

i) Compute the appropriate incident angle(that is the polarization or Brewster's angle)

ii)At what angle(from the normal) will the transmitted beam propagate through the water(that is, what is the angle of refraction)

iii)What is the angle between the reflected and refracted beams.

The Attempt at a Solution


i) n2cos(θo)-n1√[(1-(n21/n22)sin2o)]

(n22/n21)=tan2o)+1-(n21/n22)tan2o)

tan2o)={[(n22/n21-1]/[1-(n21/n22)]}=(n22/n21)

tan(θo)=(n2/n1)=(1.33/1)

θo=tan-1(1.33)=53°

Homework Statement




and that's as far as I could get. :/ I'm pretty sure part(i) is right.
Hello squirrelly. Welcome to PF !

ii) Use Snell's Law to find the angle of refraction.

iii) Draw a sketch. Use geometry.
 

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