What is force if acceleration is .75? (inclined plane)

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SUMMARY

The problem involves calculating the required horizontal force F to slide a 20kg box up a 30-degree incline with a specified acceleration of 0.75 m/s², while overcoming an 80N friction force. The correct calculation shows that the force F must equal 220N to achieve the desired acceleration, as derived from the equation F - Ff - Fn = ma. The initial miscalculation of 193N resulted from neglecting the net force required for acceleration, emphasizing the importance of applying Newton's laws correctly.

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skysunsand
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Homework Statement


A horizontal force F is exerted on a 20kg box to slide it up a 30 degree incline. The friction force retarding the motion is 80N. How large must F be if the acceleration of the moving box is to be .75 m/s^2?


Homework Equations


All the forces on the box in the x and y direction have to equal zero

F=ma
F-Ff-Fn = ma


The Attempt at a Solution



Using F-Ff-Fn,

F-80-20*9.8*sin(30) = 20*.75
F-178= 15
F= 193 N

Which isn't even close to what the answer is supposed to be, which is F=220 N
 
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If the box is accelerating then there must be a net force. Newton's first law.
 
gneill said:
If the box is accelerating then there must be a net force. Newton's first law.

How does that change my equations?
 
skysunsand said:
How does that change my equations?

Draw a Free Body Diagram for the box. There must be a net force that produces an acceleration of 0.75m/s2 (acting up-slope). So what forces act along the slope?
 

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