What is Kepler's Formula and How is it Used in Circular Motion and Gravitation?

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Homework Help Overview

The discussion revolves around Kepler's Formula and its application in the context of circular motion and gravitation. Participants are exploring the accuracy of calculations related to satellite orbits.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are attempting to apply Kepler's Formula to solve a problem but are encountering discrepancies in their calculations. Questions about the validity of specific values, such as the size of a satellite orbit, are raised. There is also a discussion about the calculation of time in seconds per day.

Discussion Status

The conversation includes attempts to clarify misunderstandings and correct errors in calculations. Some participants express gratitude for the feedback received, indicating a collaborative atmosphere. However, there is no explicit consensus on the correct application of Kepler's Formula yet.

Contextual Notes

Participants are navigating through potential errors in their calculations and assumptions about orbital parameters, highlighting the importance of accuracy in such contexts.

Mongster
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Homework Statement
Find the radius R of the orbit of a geosynchronous satellite that circles the Earth. (Note that R is measured from the center of the Earth, not the surface of the Earth.)

The universal gravitational constant G is 6.67×10−11Nm2/kg2.
The mass of the earth is 5.98×1024kg.
The radius of the earth is 6.38×106m.
Relevant Equations
r^3 = (G*Mass of Earth*T^2)/(4pi^2)
Using Kepler's Formula, I tried to solve for the answer but was told that it's incorrect.
 

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Doesn't ##4 \times 10^{-7}m## seem just a little small for a satellite orbit?
 
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But that's what the calculator said!

Also, 24 x 60 is not 86400. There are 86400 seconds in a day, but that's not 24 x 60.
 
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Ahh I apologise. It's a silly mistake I've made, shouldn't have rushed through things. Thank you all for the valuable inputs!
 
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