What is Kepler's Formula and How is it Used in Circular Motion and Gravitation?

AI Thread Summary
Kepler's Formula is being discussed in relation to calculating satellite orbits, with a specific concern raised about the calculated value of 4 x 10^-7 m being too small. The user initially expressed confusion over the accuracy of their calculations. Additionally, there was a correction regarding the calculation of seconds in a day, clarifying that 24 x 60 does not equal 86400, highlighting the importance of careful calculations. The discussion emphasizes the need for accuracy in applying Kepler's Formula and performing basic arithmetic. Overall, the conversation underscores the significance of double-checking calculations in physics.
Mongster
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Homework Statement
Find the radius R of the orbit of a geosynchronous satellite that circles the Earth. (Note that R is measured from the center of the Earth, not the surface of the Earth.)

The universal gravitational constant G is 6.67×10−11Nm2/kg2.
The mass of the earth is 5.98×1024kg.
The radius of the earth is 6.38×106m.
Relevant Equations
r^3 = (G*Mass of Earth*T^2)/(4pi^2)
Using Kepler's Formula, I tried to solve for the answer but was told that it's incorrect.
 

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Doesn't ##4 \times 10^{-7}m## seem just a little small for a satellite orbit?
 
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But that's what the calculator said!

Also, 24 x 60 is not 86400. There are 86400 seconds in a day, but that's not 24 x 60.
 
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Ahh I apologise. It's a silly mistake I've made, shouldn't have rushed through things. Thank you all for the valuable inputs!
 
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