What is physical meaning of anticommuting, not anticommuting operators

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The discussion revolves around the physical meaning of anticommuting and non-anticommuting operators in quantum mechanics. It highlights that while commutating operators have simultaneous eigenstates allowing for exact measurements, the nature of anticommutators is primarily a mathematical tool relevant in quantum field theory, particularly for fermionic fields. Participants debate the implications of commutation relations on measurement uncertainty, with some asserting that anticommutators do not provide additional physical meaning beyond their mathematical utility. The conversation also touches on the complexities of measurement interpretations in quantum mechanics, emphasizing the statistical interpretation. Ultimately, the consensus leans towards viewing anticommutators as mathematical constructs rather than possessing distinct physical significance.
Roman
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hello everyone,

while studying QM you learn the physical meaning of commutating operators, namely they have simultaneous eigenstates. For observables it means, that they can be simultaneusly exactly mesured.

What is the physical meaning of anticommuting and not anticommuting operators? [A,B]_+=0, [A,B]_+\not=0
Is there any physical meaning or is it just a mathematical tool?

(sorry for my bad english)
 
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Roman said:
hello everyone,

while studying QM you learn the physical meaning of commutating operators, namely they have simultaneous eigenstates. For observables it means, that they can be simultaneusly exactly mesured.

Where did you get that ? That's incorrect.


Roman said:
What is the physical meaning of anticommuting and not anticommuting operators? [A,B]_+=0, [A,B]_+\not=0
Is there any physical meaning or is it just a mathematical tool?

The issues with anticommutators pertain to quantum field theory and they are the convenient mathematical tool which is necessary for the theory of fermionic fields to be valid.

Daniel.
 
why isn't that correct? for example [L_i,L_j]_-\not=0 means that you can't exactly measure two components of angular momentum at the same time, the same for [x_i,p_i]_-\not=0.
can you find a counter-example?

so it is just a mathematical tool?
 
The question and whole problematic of measurement is a thorny subject in quantum mechanics. This is subject to the different "interpretations". Basically i follow the "statistical interpretation" which guided Leslie Ballentine to write his excellent book on QM.
That's why i claim that what you wote above is incorrect.

Yes, anticommutators, just like commutators are nothing but a mathematical tool.

Daniel.
 
dextercioby said:
...Basically i follow the "statistical interpretation" which guided Leslie Ballentine to write his excellent book on QM.
That's why i claim that what you wote above is incorrect.

IIRC, a somewhat general expression for the uncertainty principle shows that the uncertainty in the measurement of two quantities is proportional to their commutator, which means that, regardless of interpretation, two observables can indeed be measured simultaneously if they have a vanishing commutator (with the possible exception in the case of time-dependent operators).
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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