What is the Acceleration at a Point on Earth's Surface at a Given Latitude?

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SUMMARY

The acceleration at a point on Earth's surface at latitude θ is calculated as 3.37 cm/s² * cos(θ) relative to a non-rotating reference frame. This variation in acceleration is due to the centripetal acceleration associated with Earth's rotation and the distance from the axis of rotation. Understanding this concept is crucial for solving problems related to circular motion and gravitational effects at different latitudes.

PREREQUISITES
  • Centripetal acceleration concepts
  • Understanding of circular motion dynamics
  • Basic knowledge of Earth's rotation and latitude
  • Familiarity with physics problem-solving techniques
NEXT STEPS
  • Study the principles of centripetal acceleration in detail
  • Learn about the effects of latitude on gravitational acceleration
  • Explore the mathematical derivation of acceleration formulas for rotating bodies
  • Review problem-solving strategies for circular motion in physics
USEFUL FOR

Students and educators in physics, particularly those focusing on mechanics and circular motion, as well as anyone interested in understanding the effects of Earth's rotation on acceleration at various latitudes.

syang9
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"show that a point on the surface of the Earth at latitude theta from the equator has an acceleration of magnitude 3.37cm/s^2*cos(theta) relative to a reference fram not rotating with the earth."

i really have no idea how to approach this problem. i don't really understand why the acceleration at a point above or below the equator should be different than the acceleration at the equator. could anyone provide a hint or two as to how i should start?

many thanks.
 
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Hint1: Centripetal acceleration.
Hint2: Distance from the axis of rotation.
 
thanks a lot guys, you were a lot of help!
 

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