What is the application of the Residue Theorem in finance?

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SUMMARY

The discussion centers on the application of the Residue Theorem in finance, specifically referencing a complex integral from Lewis (2001). The integral involves evaluating a contour integral related to the function \( \Phi^{\ast}(u) \) and requires understanding the relationship between this integral and its real part. Participants express a need for clearer explanations and references to effectively utilize the Residue Theorem for financial applications.

PREREQUISITES
  • Complex analysis fundamentals
  • Residue Theorem applications
  • Understanding of contour integrals
  • Familiarity with financial mathematics concepts
NEXT STEPS
  • Study the Residue Theorem in detail, focusing on its applications in finance
  • Learn about contour integration techniques
  • Explore complex functions and their real parts in financial contexts
  • Review Lewis (2001) for specific examples of the Residue Theorem in financial modeling
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Mathematicians, finance professionals, and students seeking to apply complex analysis techniques, particularly the Residue Theorem, to financial problems and models.

Feanor
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Hi everyone.
I'm a brazilian mathmatician that didn't studied complex analysis. I study finance and now I'm needing to study that.
In a paper of Lewis (2001) I found an expression that I couldn't understand.
Does anyone can help me with that? They say they use the Residue theorem but I couldn't make the calculations using the versions of this theorem that I found.
The equality is the following:


$ \int_{i Im(u)-\infty} ^{i Im(u)+ \infty} \left( \int_{0} ^{\infty} e^{iuA_t} \Phi^{\ast}(u)dx \right) du=
\pi + 2 \left( \int_{0} ^{\infty} Re \left[ \frac{e^{-iulnK} \Phi^{\ast}(-u) } {iu}\right] du \right) $
(jpg attached for non tex users)
Could you send me reference that I could read and understand the above?

Thanks!
 

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Come on people...
Any suggestions on how to solve it?
I basically need a relation between a contour integral and the real part of another one.

Thanks!
 

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