What is the area of a triangle given (2, 3), (4, 5), and (6, 7)?

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Discussion Overview

The discussion revolves around finding the area of a triangle given three points in a Cartesian coordinate system: (2, 3), (4, 5), and (6, 7). Participants explore various methods for calculating the area, including using a specific formula and alternative approaches.

Discussion Character

  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents a formula for calculating the area of a triangle based on the coordinates of its vertices, suggesting a straightforward application of the formula.
  • Another participant questions the reliance on a formula and asks for alternative methods to find the area.
  • Some participants propose using the distance formula and Heron's Formula as methods to determine the area without a direct formula.
  • A later reply indicates that the area will be zero because the three points are collinear, challenging the initial assumption that a triangle can be formed.
  • Further discussion includes reiteration of the distance formula and Heron's Formula as effective methods for calculating the area.

Areas of Agreement / Disagreement

Participants express disagreement regarding the possibility of forming a triangle with the given points, with some asserting that the area is zero due to collinearity, while others focus on methods for calculating the area assuming a triangle can be formed.

Contextual Notes

The discussion does not resolve the implications of collinearity on the area calculation, and there are multiple proposed methods that may depend on different assumptions about the points.

mathdad
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Given (2, 3), (4, 5), (6, 7), find the area using the formula below.

Note: (a, b) (c, d) (e, f)

a = 2
b = 3

c = 4
d = 5

e = 6
f = 7

A = (1/2)[(ad - cb) + (cf - ed) + (eb - af)]

Just plug and chug, right?
 
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Suppose you weren't given a formula into which you may "plug and chug"...can you outline a method you could use to find the area?
 
1. Apply distance formula 3 times.

2. Heron's Formula
 
Given (2, 3), (4, 5), (6, 7), find the area using the formula below.

Note: (a, b) (c, d) (e, f)

a = 2
b = 3

c = 4
d = 5

e = 6
f = 7

A = (1/2)[(ad - cb) + (cf - ed) + (eb - af)]

the area will be zero ... those three points are collinear
 
MarkFL said:
Suppose you weren't given a formula into which you may "plug and chug"...can you outline a method you could use to find the area?

1. Apply distance formula 3 times.

2. Heron's Formula.
 
RTCNTC said:
1. Apply distance formula 3 times.

2. Heron's Formula.

Yes, that's likely the quickest way to get the area without an explicit formula for the area of a triangle formed by 3 points in the plane. (Yes) I once posted a tutorial here on deriving a general formula:

http://mathhelpboards.com/math-notes-49/finding-area-triangle-formed-3-points-plane-2954.html

And it relies on the following derivation:

http://mathhelpboards.com/math-notes-49/finding-distance-between-point-line-2952.html
 
Great information.
 

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