What is the Average Speed for a Car Trip with Different Constant Speeds?

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Homework Help Overview

The discussion revolves around calculating the average speed of a car trip where the driver travels at different constant speeds for specified durations and also accounts for additional time spent not driving. The problem involves understanding how to incorporate all time spent, including stops, into the average speed calculation.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the calculation of total time by summing driving times and questioning the exclusion of time spent during stops. There is a focus on understanding the implications of including all time in the average speed formula.

Discussion Status

Some participants have provided guidance on the necessity of including the time spent not driving in the average speed calculation. There is an acknowledgment of the misunderstanding regarding the total time, and one participant indicates they will attempt to recalculate based on the feedback received.

Contextual Notes

Participants are discussing the average speed in the context of a homework problem, which includes specific time intervals and speeds, as well as a total distance that must be accounted for in the calculations.

Ripcurl
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Homework Statement


A person travels by car from one city to another with different constant speeds between a pair of cities. She drives for 30.3 min at 85.2 km/h, 14.4 min at 91.1 km/h, and 48.9 min at 43.1 km/h, and spends 19.1 min eating lunch and buying gas. The distance between the initial and final cities along this route is 100.0165 km. Find the average speed for the trip. Answer in units of km/h.


Homework Equations


AvgSpeed=totaldistance/totaltime


The Attempt at a Solution


I added up all of the times (30.3 min+14.4 min+48.9 min) and got 93.6 min. I converted this to hours by dividing by 60 and got 1.56 hours. Then I divided 100.0165 by 1.56 hours and got 64.11314103. (I use the whole solution. I don't round unless I have to.) It was incorrect. If average speed equals total distance over total time, then what did I do wrong? I know I don't use that 19.2 min because it's just extra time that was spent eating and buying gas. I don't need that. So what am I doing wrong?
 
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Don't forget the time spent getting gas (speed = 0). You'll have to include that
 
Ripcurl said:

Homework Statement


A person travels by car from one city to another with different constant speeds between a pair of cities. She drives for 30.3 min at 85.2 km/h, 14.4 min at 91.1 km/h, and 48.9 min at 43.1 km/h, and spends 19.1 min eating lunch and buying gas. The distance between the initial and final cities along this route is 100.0165 km. Find the average speed for the trip. Answer in units of km/h.


Homework Equations


AvgSpeed=totaldistance/totaltime


The Attempt at a Solution


I added up all of the times (30.3 min+14.4 min+48.9 min) and got 93.6 min. I converted this to hours by dividing by 60 and got 1.56 hours. Then I divided 100.0165 by 1.56 hours and got 64.11314103. (I use the whole solution. I don't round unless I have to.) It was incorrect. If average speed equals total distance over total time, then what did I do wrong? I know I don't use that 19.2 min because it's just extra time that was spent eating and buying gas. I don't need that. So what am I doing wrong?

you do need that, because during that time, the person traveled at a speed of zero.
 
Oh, wait, I see what you're saying. Hold on, I'll try it. One sec. :3
 
Yes, and he still spent an extra 19.2 mins on the trip. You can't just forget about that time.

Just think about running around your block. If you run at a constant speed of 10km/hr, your average speed is obviously, 20km/hr. But if you stop for 30 seconds to take a breath halfway through, your average speed goes down.

You must include the 19.2 mins
 
Alright, I got it! Thank you very much!
 
CaptainEvil said:
Just think about running around your block. If you run at a constant speed of 10km/hr, your average speed is obviously, 20km/hr.
That's not at all obvious!:wink:
 
lol my mistake. obv meant 10km/hr
 
Ha ha, I kinda did a double take when I saw that too, but I knew what you meant, obviously. :wink:

But I got the question right! Thanks again for the help! o:)
 

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