What is the Average Speed for a Car Trip with Different Constant Speeds?

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SUMMARY

The average speed for a car trip involving multiple constant speeds is calculated by dividing the total distance by the total time, including all stops. In this case, the traveler drove for 30.3 minutes at 85.2 km/h, 14.4 minutes at 91.1 km/h, and 48.9 minutes at 43.1 km/h, totaling 93.6 minutes of driving time. However, the 19.1 minutes spent eating and buying gas must also be included, resulting in a total time of 112.7 minutes. The correct average speed is approximately 53.4 km/h when calculated using the total distance of 100.0165 km over the total time in hours.

PREREQUISITES
  • Understanding of average speed calculation
  • Basic knowledge of unit conversion (minutes to hours)
  • Familiarity with distance, speed, and time relationships
  • Ability to perform arithmetic operations with time and distance
NEXT STEPS
  • Learn how to convert time units effectively for speed calculations
  • Study the impact of stops on average speed in travel scenarios
  • Explore real-world applications of average speed in logistics and transportation
  • Investigate the differences between average speed and instantaneous speed
USEFUL FOR

This discussion is beneficial for students studying physics or mathematics, transportation planners, and anyone interested in understanding the implications of travel time on average speed calculations.

Ripcurl
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Homework Statement


A person travels by car from one city to another with different constant speeds between a pair of cities. She drives for 30.3 min at 85.2 km/h, 14.4 min at 91.1 km/h, and 48.9 min at 43.1 km/h, and spends 19.1 min eating lunch and buying gas. The distance between the initial and final cities along this route is 100.0165 km. Find the average speed for the trip. Answer in units of km/h.


Homework Equations


AvgSpeed=totaldistance/totaltime


The Attempt at a Solution


I added up all of the times (30.3 min+14.4 min+48.9 min) and got 93.6 min. I converted this to hours by dividing by 60 and got 1.56 hours. Then I divided 100.0165 by 1.56 hours and got 64.11314103. (I use the whole solution. I don't round unless I have to.) It was incorrect. If average speed equals total distance over total time, then what did I do wrong? I know I don't use that 19.2 min because it's just extra time that was spent eating and buying gas. I don't need that. So what am I doing wrong?
 
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Don't forget the time spent getting gas (speed = 0). You'll have to include that
 
Ripcurl said:

Homework Statement


A person travels by car from one city to another with different constant speeds between a pair of cities. She drives for 30.3 min at 85.2 km/h, 14.4 min at 91.1 km/h, and 48.9 min at 43.1 km/h, and spends 19.1 min eating lunch and buying gas. The distance between the initial and final cities along this route is 100.0165 km. Find the average speed for the trip. Answer in units of km/h.


Homework Equations


AvgSpeed=totaldistance/totaltime


The Attempt at a Solution


I added up all of the times (30.3 min+14.4 min+48.9 min) and got 93.6 min. I converted this to hours by dividing by 60 and got 1.56 hours. Then I divided 100.0165 by 1.56 hours and got 64.11314103. (I use the whole solution. I don't round unless I have to.) It was incorrect. If average speed equals total distance over total time, then what did I do wrong? I know I don't use that 19.2 min because it's just extra time that was spent eating and buying gas. I don't need that. So what am I doing wrong?

you do need that, because during that time, the person traveled at a speed of zero.
 
Oh, wait, I see what you're saying. Hold on, I'll try it. One sec. :3
 
Yes, and he still spent an extra 19.2 mins on the trip. You can't just forget about that time.

Just think about running around your block. If you run at a constant speed of 10km/hr, your average speed is obviously, 20km/hr. But if you stop for 30 seconds to take a breath halfway through, your average speed goes down.

You must include the 19.2 mins
 
Alright, I got it! Thank you very much!
 
CaptainEvil said:
Just think about running around your block. If you run at a constant speed of 10km/hr, your average speed is obviously, 20km/hr.
That's not at all obvious!:wink:
 
lol my mistake. obv meant 10km/hr
 
Ha ha, I kinda did a double take when I saw that too, but I knew what you meant, obviously. :wink:

But I got the question right! Thanks again for the help! o:)
 

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