Undergrad What is the best way to emphasize the proportion of x or y in a dataset?

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To emphasize the proportion of variables x and y in a dataset, the formulas x/(x+y) and y/(x+y) are used to calculate their respective proportions. When x is significantly larger than y, the proportion of x approaches 1, indicating a high emphasis on x. However, if both x and y increase simultaneously, the proportion of x may not necessarily increase, which highlights the importance of using ratios for comparison. An alternative approach suggested involves generating two values, P and N, where P increases with higher x and N increases with higher y, using the formulas P=x/(1+x) and N=y/(1+y). This method aims to provide a clearer distinction in emphasizing the contributions of x and y.
adan
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Hi,
There are two variables x and y. I compute a proportion of the x as x/(x+y), and the proportion of y as y/(x+y). I want to emphasize more on the amount of x or y. If x is high then the proportion should be high.
Using the above formulas if x=4229, y= 80, then x proportion = 0.981, when x=4617 and y=91, then x proportion approximately equal 0.981.

I hope I made it clear and I would appreciate any suggestion.

Thanks
 
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adan said:
Hi,
There are two variables x and y. I compute a proportion of the x as x/(x+y), and the proportion of y as y/(x+y). I want to emphasize more on the amount of x or y. If x is high then the proportion should be high.
Using the above formulas if x=4229, y= 80, then x proportion = 0.981, when x=4617 and y=91, then x proportion approximately equal 0.981.

I hope I made it clear and I would appreciate any suggestion.
Do you have a question?

The proportions are, more clearly, the proportion or ratio of x to the sum of x and y and the ratio of y to the sum of x and y. Whichever variable is larger will make for a higher proportion of that variable to the sum of the two variables.
 
adan said:
If x is high then the proportion should be high.
At the same y, it is. If both x and y increase then the proportion of x doesn't have to increase. That's the point of taking the ratio. If you just want to compare absolute numbers, use the absolute numbers.
 
Thanks all. I think I would like to do something that can't be done using the ratio. The idea is to generate two values (P,N) between 0 and 1. If x is high P increases, and if y is high N increases. Where x and y >= 0.
I will try P=x/(1+x) and N = y/(1+y)
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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