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Master1022

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- What terms in the equation (from the linked paper) are vectors or scalars?

Hi,

This is a simple question that I just wanted to clarify. I was reading the following paper on

- ##f## is a vector

- ## S ## is a matrix

- ## \alpha ## is a scalar

- I am not too sure about ##y##: could be a vector or a scalar.

- ##\nu##: I am not too sure, but I think it could be referring to a specific node? That is, ## f(\nu) ## could be the value of the vector ## f## at node ## \nu ##.

- ## y ##: I am not sure, but I think it is a vector (see reasoning below).

- That would make sense mathematically, but does that mean that we are using the same scalar ## y ## the equation for all nodes. That is, it doesn't matter what node ## \nu ## we are considering, we will always have the same ## y ## scalar in the equation? However, there is another equation above (shown below) which uses y as follows. This suggests that ##y## is a vector because then we have matrix-vector multiplication:

- It could be a vector (as suggested by image above), but then we are adding a vector ## (1 - \alpha) y ## to a scalar ## \alpha S f ## is a vector, and we are extracted the value at a certain node ## \nu ##, so it is a scalar. Therefore, it seems unlikely that ## y ## is a vector unless my interpretation of ## \nu ## is incorrect.Apologies if this is sparse with information. I didn't want to rewrite the paper in this post and I am unsure of some of the definitions of variables in there. Any help would be greatly appreciated.

This is a simple question that I just wanted to clarify. I was reading the following paper on

**label propagation**:__HERE__and I can't understand whether the terms are vectors or scalars in one of the equations - specifically, equation (2.15) shown in the image below.**My understanding:**- ##f## is a vector

- ## S ## is a matrix

- ## \alpha ## is a scalar

- I am not too sure about ##y##: could be a vector or a scalar.

- ##\nu##: I am not too sure, but I think it could be referring to a specific node? That is, ## f(\nu) ## could be the value of the vector ## f## at node ## \nu ##.

- ## y ##: I am not sure, but I think it is a vector (see reasoning below).

*Case is ## y ## is a scalar:*- That would make sense mathematically, but does that mean that we are using the same scalar ## y ## the equation for all nodes. That is, it doesn't matter what node ## \nu ## we are considering, we will always have the same ## y ## scalar in the equation? However, there is another equation above (shown below) which uses y as follows. This suggests that ##y## is a vector because then we have matrix-vector multiplication:

*Case if ## y ## is a vector:*- It could be a vector (as suggested by image above), but then we are adding a vector ## (1 - \alpha) y ## to a scalar ## \alpha S f ## is a vector, and we are extracted the value at a certain node ## \nu ##, so it is a scalar. Therefore, it seems unlikely that ## y ## is a vector unless my interpretation of ## \nu ## is incorrect.Apologies if this is sparse with information. I didn't want to rewrite the paper in this post and I am unsure of some of the definitions of variables in there. Any help would be greatly appreciated.