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## Homework Statement

What is the change in gravitational potential energy of a 6200 kg satellite that lifts off from Earth's surface into a circular orbit of altitude 2500 km? What percent error is introduced by assuming a constant value of g and calculating the change in gravitational potential energy from m⋅g⋅Δh?

## Homework Equations

[tex]E_{p}=mgh[/tex]

[tex]F_{g}=G((m_{1}m_{2})/(r^{2}))[/tex]

## The Attempt at a Solution

Well, the change in potential energy is simply mgh = 6200kg*9.81m/s/s*2500000m = 152055000000 which is the change in p energy.. then the rest i am lost.. i know there would be an error because gravity is not 9.81 m/s as you go on, it gets less and less as you leave earth..

thanks for your time