MHB What is the compatibility condition for the given operators and constants?

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The discussion centers on establishing the compatibility condition for the operators \(L\) and \(M\) in the equations \(L\phi = \lambda\phi\) and \(\phi_t = M\phi\). The condition is derived as \(L_t + [L, M] = 0\), where \([L, M]\) represents the commutator. The derivation involves manipulating the expressions to show that \(L_t\phi + LM\phi - \lambda M\phi = 0\). A clarification is made regarding the misuse of \(\lambda\) as an operator, emphasizing that it is a constant. The discussion concludes with a reference to the Inverse Scattering Transform and Lax pairs, indicating a deeper mathematical context.
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Given
\begin{align}
L\phi &= \lambda\phi\\
\phi_t &= M\phi
\end{align}
where \(L\) and \(M\) are operators and \(\lambda\) a constant.
I want to show the compatibily condition is \(L_t + [L,M] = 0\) where \([,]\) is the commutator.
\[
(L\phi)_t = L_t\phi + L\phi_t = \lambda\phi_t = \lambda M\phi
\]
That is, we have \(L_t\phi + L\phi_t - \lambda M\phi = L_t\phi + LM\phi- \lambda M\phi = 0\).
\begin{align}
[L_t + LM - \lambda M]\phi &= 0\\
L_t + LM - \lambda M &= 0
\end{align}
Can I just let \(\lambda = L\) which doesn't make since sense one is an operator and the other a constant? If not, how do I get the commutator \(LM - ML\) part?
 
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Ah, I see you are doing the Inverse Scattering Transform with Lax pairs. You have $\lambda M \phi$. Since $\lambda$ is a scalar, rearrange thus: $\lambda M \phi=M(\lambda \phi)=M L \phi$. You can go from there.
 

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