What is the concentration of the Ba(OH)2 solution in mol/L?

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SUMMARY

The concentration of the Ba(OH)2 solution is calculated using the mass difference of the crucible containing the precipitate. The mass of Ba(OH)2 is determined to be 0.129 g, derived from the difference between the mass of the crucible with precipitate (17.539 g) and the empty crucible (17.410 g). The molar mass of Ba(OH)2 is 171.34 g/mol, allowing for the calculation of moles, which is approximately 0.000754 moles. Consequently, the concentration of the Ba(OH)2 solution is 0.0754 mol/L when converted to a 10 mL volume.

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Homework Statement



suppose that for a 10 mL sample of Ba(OH)2 solution, the mass of the cubicle with precipitate is 17.539g and the mass of the empty cubicle is 17.410g. calculate the concentration of the Ba(OH)2 solution from this data.

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The Attempt at a Solution

 
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You can find the molar mass of Ba(OH)2 with the periodic table, the change in mass of the crucible is the mass of the Ba(OH)2, which means you can find the # of moles of Ba(OH)2 you got. And finally you know that concentration is mole per liter.
 

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