What is the connection between energy eigenstates and position?

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SUMMARY

The discussion centers on the relationship between energy eigenstates and position in quantum mechanics, specifically through the lens of the time-independent 1-D Schrödinger equation, Hψ = (\frac{-\hbar^2}{2m}\frac{d^2}{dx^2} + V)ψ(x) = Eψ(x). The energy eigenstate ψ, also known as the wavefunction, allows for the calculation of the probability density |ψ(x)|^2, which indicates the likelihood of finding a particle at a specific position x. The unique aspect of energy eigenstates lies in their ability to facilitate time evolution of states, as opposed to other observables, which do not provide the same temporal dynamics. The derivation of the Schrödinger equation, rooted in De Broglie's relations and the least action principle, establishes energy as a scalar eigenvalue, highlighting its significance in quantum mechanics.

PREREQUISITES
  • Understanding of the time-independent Schrödinger equation
  • Familiarity with quantum mechanical concepts such as wavefunctions and eigenstates
  • Knowledge of Hilbert space and linear operators in quantum mechanics
  • Basic grasp of De Broglie's relations and the least action principle
NEXT STEPS
  • Explore the implications of the Born postulate in quantum mechanics
  • Study the role of Hilbert space in quantum state representation
  • Investigate the relationship between momentum eigenstates and position probability
  • Learn about the time evolution of quantum states using the Schrödinger equation
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Students and professionals in quantum mechanics, physicists exploring wave-particle duality, and researchers interested in the foundational aspects of quantum theory.

jeebs
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The first thing I remember hearing about in QM was the time-independent 1-D Schrödinger equation, Hψ = (\frac{-\hbar^2}{2m}\frac{d^2}{dx^2} + V)ψ(x) = Eψ(x). This is an eigenvalue equation, the Hamiltonian operator H operating on the energy eigenstate ψ to produce the product of the energy eigenvalue, E, and ψ.

However, we also come to know this state ψ by another name, the "wavefunction", and we find that if we take |ψ(x)|^2 we find the probability of finding our particle at at position x.

My question is, what is it about the eigenstates of the energy operator in particular that should mean we can find out this information about the likelihood of a particle occupying a certain position x upon measurement? I don't see the connection - especially seeing as we could take a free particle (V=0) so that the energy of the particle has no dependence on position, only momentum?
In other words, why don't we take any other eigenstate for any other observable quantity, square that and use that for our position probability?
 
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You can choose to express your wavefunction in any complete basis. The thing that's special about the energy eigenbasis is it gives you an easy way to evolve the states in time. The Born postulate has nothing to do with energy eigenbases.
 
the wave function solutions of the Schrödinger equation for any system are solutions in a "state space" within the Hilbert Space. The Hilbert space is a space where the elements of the space are solutions to the wave equation (where the operation is just the inner product). A state of a quantum mechanical system is then a vector in the Hilbert space, and observables (which act as operators in Quantum mechanics) are a type of linear operator. Like any linear operator there exists a matrix representation allowing for our eigen value to be relevant. But the fact that these eigen-values correspond to the systems energy comes solely from the derivation of the Schrödinger equation which uses De Broglie's relations and the least action principle to find a wave form from particle quantisation. The fact energy became the scalar acting as a eigen-value for an eigen-value equation was a beautiful by-product.
The state space is not limited to a position representation. ANY observable my act as the linear operator in our Hilbert space.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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