What is the Coulomb's Law formula for calculating point charges?

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SUMMARY

The discussion centers on calculating two point charges using Coulomb's Law, given their sum of 6 microcoulombs and an attractive force of 0.9 Newton at a distance of 0.4 meters in a vacuum. The relevant formula used is Coulomb's Law, expressed as F = (q1 * q2) / (4 * π * ε0 * r²). Participants debated whether to use q1 * q2 or -q1 * q2 in the formula, concluding that while the magnitude remains unchanged, clarity in formulation is crucial for understanding.

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Homework Statement




The sum of two point charges is 6 micro coulomb. They attract each other with a force of 0.9 Newton, when kept 0.4 m apart in vacuum. calculate the charges.

Homework Equations



since it is attractive force, i formed the equation q1-q2= 6 *106 and got the relevant equation for q2
then we have the coulomb's law f = q1*q2/4 *3.14*epsilon0 *r2
Should i use - q1q2 or simply q1*q2 in the coulomb's formula

The Attempt at a Solution



 
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hi logearav! :smile:
logearav said:
The sum of two point charges is 6 micro coulomb. They attract each other with a force of 0.9 Newton, when kept 0.4 m apart in vacuum. calculate the charges.

Should i use - q1q2 or simply q1*q2 in the coulomb's formula

what difference does it make? … the magnitude of the result will be the same anyway :confused:

(btw, i assume you used q1 - q2 (instead of q1 + q2) because you were trying to simplify things …

not much point in simplifications if they confuse you later! :rolleyes:)
 
Thanks a lot tiny-tim.
 

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