What is the Criterion for Total Internal Reflection?

  • Thread starter Thread starter Larrytsai
  • Start date Start date
  • Tags Tags
    Optics
Larrytsai
Messages
222
Reaction score
0
Hey, on my test today on the bonus question was asking : if a light ray shines at 50 degrees into a diamond then enters air at what angle? n for diamond = 2.5
n for air = 1.00.

I know the answer is total internal reflection cause i guessed it and got it right, but how do you prove it and how do u knw if it is total internal reflection?
 
Physics news on Phys.org
also if you use the formula ni sin theta i= nr sin theta r you end up not being able to complete the formula
 
Well, what is the criterion for Total Internal Reflection? You should know this. It occurs when a light ray is moving from a more optically dense medium (n2 below) into a less optically dense medium (smaller index of refraction n1 below), and the angle of incidence is so large, that Snell's law breaks down...it produces a sine for the refracted angle that is greater than one. In fact, the critical angle occurs when the sine is equal to one. In other words:

[tex]n_2 \sin \theta_2 = n_1 \sin \theta_1[/tex]

[tex]\frac{n_2}{n_1} \sin \theta_2 = \sin \theta_1 = 1[/tex]

[tex]\sin \theta_2 = \frac{n_1}{n_2}[/tex]

[tex]\theta_2 = \theta_{\textrm{critical}} = \sin^{-1}\left(\frac{n_1}{n_2}\right)[/tex]

This is the critical angle...for angles larger than this, the angle of the refracted ray is undefined...and there is no refracted ray. Instead, total internal reflection occurs.
 
Last edited:

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
6K