What Is the Critical Angle for Light in a Submerged Fiber Optic Cable?

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SUMMARY

The critical angle for light to remain within a submerged fiber optic cable can be calculated using Snell's Law. Given the refractive index of the fiber optic (n = 1.5) and the refractive index of water (n = 1.33), the critical angle (C) is determined by the formula sin(C) = n2/n1, where n1 is the refractive index of the fiber optic and n2 is the refractive index of water. This results in a critical angle of approximately 61.03 degrees.

PREREQUISITES
  • Understanding of Snell's Law
  • Knowledge of refractive indices
  • Basic trigonometry
  • Familiarity with fiber optic technology
NEXT STEPS
  • Study the derivation of Snell's Law in optics
  • Research the properties of light in different media
  • Explore applications of fiber optics in telecommunications
  • Learn about total internal reflection in optical fibers
USEFUL FOR

Students in physics or engineering, optical engineers, and anyone involved in the design or application of fiber optic systems.

dev-hud
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A fiber optic (n = 1.5) is submerged in water (n = 1.33). What is the critical angle for light to stay inside the cable?


i am so confuzed. this is the final question of my paper and i am stuck on a couple questions before this so it is obvious i would get this. i just need a start please.
 
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dev-hud said:
A fiber optic (n = 1.5) is submerged in water (n = 1.33). What is the critical angle for light to stay inside the cable?


i am so confuzed. this is the final question of my paper and i am stuck on a couple questions before this so it is obvious i would get this. i just need a start please.

sinC = 1/n
 

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