What is the difference between SIN and SINH?

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There are SIN and SINH. The first one is familiar as SINUS on calculus (or trigonometry), but, I don’t know what SINH means. Can anybody here explain me what is meant by “H” letter on the SINH? Please advance
 
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tomcenjerrym said:
There are SIN and SINH. The first one is familiar as SINUS on calculus (or trigonometry), but, I don’t know what SINH means. Can anybody here explain me what is meant by “H” letter on the SINH? Please advance

It's Hyperbolic Sine. The H is abbreviated for Hyperbolic. you can read it up here.

[tex]\sinh x = \frac{e ^ {x} - e ^ {-x}}{2}[/tex]

[tex]\cosh x = \frac{e ^ {x} + e ^ {-x}}{2}[/tex]

[tex]\tanh x = \frac{\sinh x}{\cosh x} = \frac{e ^ {x} - e ^ {-x}}{e ^ {x} + e ^ {-x}}[/tex]

[tex]\coth x = \frac{\cosh x}{\sinh x} = \frac{e ^ {x} + e ^ {-x}}{e ^ {x} - e ^ {-x}}[/tex]
 
circular functions and hyperbolic functions.

given any curve f and a fixed point on it and a direction, you get two functions. i.e. given input t, go along the curve a distance t, then look at the x and y coordinates x(t) = cosf(t) and y(t) = sinf(t).
 
another way to think of it is

cosh(ix) = cos(x)
sinh(ix) = i*sin(x)
 
Just to add to this list:
The "fundamental solutions" to the differential equation y"+ y= 0 are cos(x) and
sin(x). "Fundamental" because if y is a solution to y"+ y= 0, satifying y(0)= A, y'(0)= B, then y(x)= A cos(x)+ B sin(x).

The fundamental solutions to the differential equation y"- y= 0 are cosh(x) and sinh(x). If y is a solution to y"- y= 0 satisfying y(0)= A, y'(0)= B, then y(x)= A cosh(x)+ B sinh(x).
Normally, the general solution to y"- y= 0 is written C1[/sup]ex+ C2 e-x but that is harder to evaluate at x= 0.