What is the direction of the E field at point P due to the sphere?

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SUMMARY

The electric field at point P, located at coordinates (1 m, 0.5 m), is influenced by both a charged infinite plane and a sphere. The plane, charged with a surface density of σ = 2μC/m², contributes an electric field of E_plane = -113 kN/C in the negative x-direction. The sphere, with a volume charge density of ρ = -6μC/m³ and a radius of 0.8 meters, requires the application of Gauss's law to determine the electric field contribution at point P. The direction of the electric field due to the sphere is determined by the symmetry of the charge distribution.

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Homework Statement


an infinite plan,parallel to the yz plan which passes from x=2 meter, is charged equally with the σ= 2μC/m^2 .A sphere with a radius 0.8 meters has its center in the in x=1 m,y=0 and has ρ=-6μC/m^3.Find the value of the intensity of the electric field in the point x=1 m and y=0.5 m.



Homework Equations


the figure :
a7Hacah.jpg



The Attempt at a Solution


The E at P is = Eplane + Esphere
I find the E of plane =(-σ/2∈ )* i=-113kN/C * i
To find the E of sphere, I have to use the formula E=(4*pi/3)*k*r*ρ*rˆ... I have every known data,I just need to find the unit vector r or (rˆ)..how to find it?
 
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By symmetry, what is the direction of the E field at point p due to the sphere by itself?
Hint: invoke Gauss's law.
 

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