What is the Direction of the Velocity of a Particle in a Rotating Tube?

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SUMMARY

The discussion focuses on the dynamics of a particle released from a rotating tube of length 2R, which rotates in the horizontal xy plane with a constant angular velocity ω about the z-axis. The particle, with mass m, is released at a distance R from the origin. Upon release, the direction of the particle's velocity is determined to be v0/r, where v0 represents the tangential velocity at the point of release. This conclusion is critical for understanding motion in rotating reference frames.

PREREQUISITES
  • Understanding of angular velocity and its effects on motion
  • Familiarity with basic physics concepts such as mass and velocity
  • Knowledge of rotating reference frames
  • Concept of frictionless motion in physics
NEXT STEPS
  • Study the principles of angular momentum in rotating systems
  • Learn about the Coriolis effect in rotating frames
  • Explore the equations of motion for particles in circular paths
  • Investigate the implications of frictionless surfaces in dynamics
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in classical mechanics, particularly those studying rotational dynamics and particle motion in rotating systems.

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Ok so I have this tube of length 2R that rotates in the horizontal xy plane with constant angular velocity [tex]\omega[/tex] about the z axis. And there is this particle of mass m that is released a distance R from the origin. Assuming the tube is frictionless I need to find the direction of the velocity of the particle just as it leaves the tube?

Picture:
[PLAIN]http://img696.imageshack.us/img696/4020/tubev.png

Any help is appreciated!
 
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I am telling Sri about this in class tomorrow


But the answer is v0/r
 

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