mathuravasant
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State the domain and range for one cycle of y=cos(3(x - 45°)) +2 Show your work.
The domain of the function y=cos(3(x - 45°)) + 2 for one cycle is defined as the interval 0 ≤ 3(x - 45°) ≤ 360°, which translates to the values of x being in the range of -45° ≤ x ≤ 90°. The range of the function is determined by the cosine function's output, which oscillates between -1 and 1. Therefore, the range of y=cos(3(x - 45°)) + 2 is 1 ≤ y ≤ 3. Graphing the function provides a visual representation of these values.
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Please show us what you have tried and exactly where you are stuck.mathuravasant said:State the domain and range for one cycle of y=cos(3(x - 45°)) +2 Show your work.
You are having a great deal of trouble with these. I suspect the biggest cause isn't in the problems but in the definitions. I would suggest having a 3 x 5 card (or some other modern equivalent) stating what the domain, range, frequency, wave number, horizontal shift (or phase), and vertical shift are for each.mathuravasant said:like how do you find domain and range off from that given equation I just don't know what to do