What Is the Energy Difference Between Octane and Methanol as Fuel Alternatives?

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Discussion Overview

The discussion revolves around comparing the energy differences between octane and methanol as fuel alternatives, focusing on their energy content per gram and the implications for fuel tank size based on efficiency in automotive applications.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant expresses confusion about the problem and seeks assistance in understanding the energy comparison between octane and methanol.
  • Another participant calculates the molecular weights of octane and methanol, providing the energy produced per gram for each fuel, with octane yielding 48.1 kJ/g and methanol approximately 19.96 kJ/g after conversion from kJ/mol.
  • The same participant further calculates the utilized energy per unit volume for both fuels, concluding that octane has a higher energy density than methanol when accounting for efficiency.
  • One participant questions the composition of gasoline, suggesting that toluene is a significant component, while noting that the octane rating relates to anti-knock properties.
  • A later reply expresses gratitude for the clarity provided by the calculations, indicating that the explanation helped in understanding the topic better.

Areas of Agreement / Disagreement

Participants generally agree on the calculations regarding energy content per gram and the implications for fuel tank size, but there is a disagreement regarding the composition of gasoline, with one participant suggesting toluene as a major component.

Contextual Notes

The discussion does not resolve the question of gasoline composition and relies on specific assumptions regarding the efficiency of fuel usage in vehicles.

sciencenerd
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gasoline/energy question...PLEASE HELP!

This is one of the problems i have to do...COMPLETELY LOST on it. I don't even know where to start or what to do. Please, please, please could someone help??

One of the serious problems that we have not yet solved is the use of fossil fuels, especially gasoline, to power our automobiles. Companies around the world are constantly trying to find a suitable replacement for gasoline. If we use octane (C8H18) as the representative of what is contained in gasoline, and compare it to methanol (CH3OH), currently a promising substitute for gasoline, what will be the energy difference on a per gram basis for the two. For the reaction of octane with oxygen to produce carbon dioxide and water, 48.1 kJ of heat are evolved per gram of octane burned. For the reaction ofmethanol, CH3OH, with oxygen to produce CO2 and gaseous water, 638.6 kJ/mole methanol. On a per gram basis, from which one will more energy be produced. The density of octane is 0.7025 g/cm3 and the density of methanol is 0.7914 g/cm3. If burning octane in an automobile is 30% efficient (i.e., 30% of the energy produced is used to move the car) and burning methanol is 40% efficient, which fuel will have the larger tank to have the same mileage capability?
 
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a good place to start is molecular weight

MW octane = 8*12+18 = 114
MW methanol = 12+3+16+1 = 32

For octane, the energy produced is 48.1 KJ/g (given)

For methanol, the energy produced is 638.6 KJ/mol (given). To convert this to KJ/g, divide by MW of methanol. Then, 638.6/32 = 19.96 KJ/g

for octane:
48.1 KJ/g * 0.7025 g/cm^3 = 33.79 KJ/cm^3 * (0.3) = 10.137 KJ/cm^3 utilized energy

for methanol:
19.96 KJ/g * 0.7914 g/cm^3 = 15.8 KJ/cm^3 * (0.4) = 6.32 KJ/cm^3 utilized energy

More energy is stored in octane per unit volume than in methanol, thus methanol will require a larger tank.
 
I though gasolene was mostly toluene; the octane specification has to do with anti-knock properties of the engine.
 
thanks so much! it makes so much more sense when i actually see it done out :)
 

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