What Is the Energy Difference for Argon-Ion Laser Transitions?

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Homework Help Overview

The discussion revolves around calculating the energy difference between two energy states in an argon-ion laser, specifically for a transition that emits light at a wavelength of 488 nm. The problem is set within the context of atomic physics and laser technology.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the appropriate formula for calculating energy, with one participant attempting to derive energy using the relationship E = hc/λ. There are questions about the correctness of the approach and the conversion of units.

Discussion Status

Some guidance has been provided regarding the formula to use, and one participant has reported a successful calculation after addressing unit conversion. However, there is no explicit consensus on the final answer, as multiple interpretations and attempts are still being explored.

Contextual Notes

Participants mention the challenge of converting units from nanometers to meters, which is a critical step in solving the problem. The original poster expresses frustration over the practice test question format and the multiple-choice options provided.

LebLlama
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Do you fancy argon-ion lasers??

I sure dont. =/

Homework Statement


I dont. This is a practice test problem and I cannot figure it out. Frustrating!

An argon-ion laser emits a blue-green beam of light with a wavelength of 488 nm in a vacuum. What is the difference in energy in joules between the two energy states for the atomic transition that produces this light?

a.
6.18 × 10–20 J


b.
1.05 × 10–20 J


c.
5.10 × 10–28 J


d.
4.08 × 10–19 J


e.
4.76 × 10–24 J



Homework Equations



See below. I am not sure its right though since I am not producing one of the multiple choice questions.

The Attempt at a Solution



This is what I came up with so far:
so we know the wavelength (l) of the light emitted.

now, E (energy) is h * n (h = Plancks constant, n = frequency)

so

E = h * n

but also, l = c T = c / n (T is the period of the oscillation of the emitted light) which means

n = c / l

so

E = h * c / l

with this formula E can be computed

(c = 3 * 10^8 m/s is the speed of light)
my answer isn't any of the above, however. :(

help? =)
 
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Try again. The formula E=hc/l is right, and if you plug in the right numbers, it DOES give you one of the answer choices.
 


I keep getting 4.07 x 10^-28

Thats a combination of c and d haha. :(
 


Update(since I know you're all eager to hear about my adventures):

I got it! I just had to convert nm to m haha. Duh.

Oh, and I got 100% on my quiz today!WOOT WOOT!

Id start breakdancing right now out of pure joy, but I don't want to snap my legs.

This means Ill get an A for 2nd semester physics. I got an A in 1st semester too and I don't even like the subject.

*llama dance*
 

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