What is the energy dissipated in the wire?

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SUMMARY

The discussion focuses on calculating the energy dissipated in a copper wire connecting two charged metal plates, each with a charge of ±12.5 nC. The maximum current in the wire is established at 4.17×105 A, and the largest electric field is determined to be 1.80×105 V/m. The participant seeks assistance in calculating the total energy dissipated in the wire, linking it to the work done by the electric field on a point charge.

PREREQUISITES
  • Understanding of electric fields and potential energy
  • Familiarity with Ohm's Law and current calculations
  • Knowledge of capacitor behavior and energy storage
  • Basic principles of electromagnetism
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  • Calculate energy dissipated using the formula U = -qEd
  • Explore the relationship between current, voltage, and resistance in circuits
  • Investigate the concept of energy conservation in electrical systems
  • Learn about the behavior of capacitors in series and parallel configurations
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Students in physics or electrical engineering, particularly those studying electromagnetism and circuit theory, will benefit from this discussion.

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Homework Statement



Two 10-cm-diameter metal plates are 1.0 cm apart. They are charged to \pm12.5 nC. They are suddenly connected together by a 0.224-mm-diameter copper wire stretched taut from the center of one plate to the center of the other.

a) What is the maximum current in the wire?
b) What is the largest electric field in the wire?
c) What is the total amount of energy dissipated in the wire?

Homework Equations





The Attempt at a Solution


i already got part a an b.. the answers are 4.17×10^5 A and 1.80×10^5 V/m , respectively

part c...i can't figure it out...how to calculate the energy?
help

i think the energy dissipated from the wire goes to the capacitor
 
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What would be the force exerted by the e-field on a point charge of q? Now how is work and hence potential energy related to this force?
 
what is the charge on the point charge

F = qE
W = Fdcos(angle)

W = qEd
U(electric potential energy ) = - W(electric)
then
U = -qEd
 

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