- #1
Zack K
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- 6
Homework Statement
A point charge of 6 × 10−9 C is located at the origin.
The magnitude magnitude at ##\langle 0.6,0,0\rangle## m is 150 N/C
Next, a short, straight, thin copper wire 5 mm long is placed along the x axis with its center at location ##\langle 0.3,0,0 \rangle## m. What is the approximate change in the magnitude of the electric field at location ##\langle 0.6,0,0\rangle##? (Approximate the polarized charges on the short copper wire as a dipole, and when calculating your answer, take the center of the wire as the point at which the net electric field is zero.)
Homework Equations
##\vec E=\frac {kq} {r^2}##
##\vec E_{wire}=\frac {2kqL} {r^3}##
The Attempt at a Solution
I calculated the electric field due to the wire using the 2nd equation. Using q as the charge of the point charge and r as 0.3. Then finding the magnitude of the electric field to the wire should give me the change in the electric field due the wire.
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