What is the Equation for Momentum in a Rifle Firing a Bullet?

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SUMMARY

The equation for momentum in a rifle firing a bullet is derived from the conservation of momentum principle. When a rifle of mass M fires a bullet of mass m at velocity v, the resulting velocity of the rifle (V) can be expressed as V = -mv/M. This indicates that the rifle recoils in the opposite direction to the bullet's motion, maintaining the system's overall momentum. The discussion confirms the accuracy of this equation and encourages further questions within the same thread.

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blackout85
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A rifle of mass M is intially at rest but free to recoil. It fires a bullet of mass m and velocity v (relative to the ground). After firing, the velocity of the rifle (relative to the ground) is:

P= m2V2 -m1v1
P= M(v-0) - m(v-0)
M(V-0) = m(V-0)
V-0= mv/M
V= -mv/M
is that right
 
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Yes, it is. Btw, you can post similar questions into the same thread next time.
 

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