- #1

mathmari

Gold Member

MHB

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Calculate the Cholesky decomposition of the matrix, the only non-vanishing elements are the diagonals $1,2,3, \lambda$ and all under and upper secondary diagonal elements are $1$.

For which $\lambda$ is the matrix singular?

Could you please explain the form of the Matrix?

Does the matrix on the diagonal have $1,2,3, \lambda$ ? So do we have a $4 \times 4$ matrix? Or are these the only non zero diagonal elements? :unsure: