What is the Geometric Centre of a Body?

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SUMMARY

The geometric centre of a body, also known as the centroid, is defined by the coordinates calculated through the integrals of the body's volume. The formulas for the x, y, and z coordinates are given by: \overline{x}= \frac{\int\int\int xdV}{\int\int\int dV}, \overline{y}= \frac{\int\int\int ydV}{\int\int\int dV}, and \overline{z}= \frac{\int\int\int zdV}{\int\int\int dV}. The denominator represents the total volume of the body. When considering constant density, the centroid coincides with the center of mass, as the density factor cancels out in the calculations.

PREREQUISITES
  • Understanding of integral calculus
  • Familiarity with volume calculations in three-dimensional geometry
  • Knowledge of density and its implications in physical bodies
  • Basic concepts of centroids and centers of mass
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  • Research the application of centroids in engineering design
  • Explore advanced integral calculus techniques for volume calculations
  • Learn about the differences between centroid and center of mass in non-uniform density scenarios
  • Investigate numerical methods for calculating centroids in complex geometries
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Students and professionals in engineering, physics, and mathematics who are involved in geometric analysis, structural design, or any field requiring an understanding of centroids and their applications.

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Could anyone tell me what actually the geometric centre of a body is?
please don't cite references from centre of mass or gravity.i want to know what it is in terms of its geometricity.
 
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You might want to google or otherwise look up "centroid". If you can find formulas describing the body it is the the x, y, and z coordinates given by
\overline{x}= \frac{\int\int\int xdV}{\int\int\int dV}
\overline{y}= \frac{\int\int\int ydV}{\int\int\int dV}
\overline{z}= \frac{\int\int\int zdV}{\int\int\int dV}

The denominator is, of course, the volume of the body.

If you don't mind my using dirty words, that is, in fact, the "center of mass" or "center of gravity" assuming a constant density where you replace dV with \rho dV, \rho being the density. Since it is constant it can be taken out of the integrals, and, since it is in both numerator and denominator, will cancel.
 

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