MHB What Is the Guessed Form Using the Method of Undetermined Coefficients?

Dustinsfl
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$$
A\exp\left(\frac{-t}{2}\right)\sin x\cosh \left(\frac{\sqrt{5}}{2}t\right) + B\exp\left(\frac{-t}{2}\right)\sin x\sinh \left(\frac{\sqrt{5}}{2}t\right)
$$

What would be the guessed form using the method of undetermined coefficients?

Also, if I had
$$
\exp\left(\frac{-t}{2}\right)\sum\left[\sin nx\left(C_n\cos\left(\frac{\sqrt{4n^2-9}}{2}t\right)+D_n\sin\left(\frac{\sqrt{4n^2-9}}{2}t\right)\right)\right],
$$
what would be the guessed form as well?
 
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dwsmith said:
$$
A\exp\left(\frac{-t}{2}\right)\sin x\cosh \left(\frac{\sqrt{5}}{2}t\right) + B\exp\left(\frac{-t}{2}\right)\sin x\sinh \left(\frac{\sqrt{5}}{2}t\right)
$$

What would be the guessed form using the method of undetermined coefficients?

Also, if I had
$$
\exp\left(\frac{-t}{2}\right)\sum\left[\sin nx\left(C_n\cos\left(\frac{\sqrt{4n^2-9}}{2}t\right)+D_n\sin\left(\frac{\sqrt{4n^2-9}}{2}t\right)\right)\right],
$$
what would be the guessed form as well?

Hi dwsmith, :)

I don't understand your question. Are you talking about the method of undetermined coefficients? If so, what is the differential equation?

Kind Regards,
Sudharaka.
 
I think what has been provided is the "right-hand side" of the differential equation, and the OP is wanting to know what form the particular solution will take.
 
I have the equation ##F^x=m\frac {d}{dt}(\gamma v^x)##, where ##\gamma## is the Lorentz factor, and ##x## is a superscript, not an exponent. In my textbook the solution is given as ##\frac {F^x}{m}t=\frac {v^x}{\sqrt {1-v^{x^2}/c^2}}##. What bothers me is, when I separate the variables I get ##\frac {F^x}{m}dt=d(\gamma v^x)##. Can I simply consider ##d(\gamma v^x)## the variable of integration without any further considerations? Can I simply make the substitution ##\gamma v^x = u## and then...

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